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49x^2=162
We move all terms to the left:
49x^2-(162)=0
a = 49; b = 0; c = -162;
Δ = b2-4ac
Δ = 02-4·49·(-162)
Δ = 31752
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{31752}=\sqrt{15876*2}=\sqrt{15876}*\sqrt{2}=126\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-126\sqrt{2}}{2*49}=\frac{0-126\sqrt{2}}{98} =-\frac{126\sqrt{2}}{98} =-\frac{9\sqrt{2}}{7} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+126\sqrt{2}}{2*49}=\frac{0+126\sqrt{2}}{98} =\frac{126\sqrt{2}}{98} =\frac{9\sqrt{2}}{7} $
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